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  • Airflare： 你这也不对啊，各种报错啊！DocumentHelper哪来的啊 ...
    XML读写
  • myali88： 为什么我用$.getJSON请求返回的始终是一个JSON格式的 ...
    jQuery+JSON

jQuery+JSON

jsonjQueryJavaServletWeb
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JqueryServlet.java 


package com.fayhong.util;

import java.io.IOException;
import java.util.List;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

import org.springframework.web.context.WebApplicationContext;
import org.springframework.web.context.support.WebApplicationContextUtils;

import com.fayhong.service.basicdata.BasicDataService;

public class JqueryServlet extends HttpServlet {
	public BasicDataService basicDataService;
	protected void doGet(HttpServletRequest req, HttpServletResponse resp)throws ServletException, IOException {
		doPost(req, resp);
	}

	protected void doPost(HttpServletRequest req, HttpServletResponse resp)
			throws ServletException, IOException {
		WebApplicationContext wac =   WebApplicationContextUtils.getRequiredWebApplicationContext(getServletContext());
		basicDataService=(BasicDataService)wac.getBean("basicDataService");
		resp.setContentType("text/html;charset=UTF-8");
		resp.setHeader("Cache-Control", "no-cache");
		JSONObject json = new JSONObject();
		List list=basicDataService.findCountry(null, null);
		try{
			JSONArray members = new JSONArray().fromObject(list);
			json.put("country", members);
		}
		catch (Exception e) {
			e.printStackTrace();
		}
		System.out.println(json.toString());
		resp.getWriter().write(json.toString());
	}

}


jqueryjson.jsp 

<%@ page contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>

	<head>
		<meta http-equiv="Content-type" content="text/html; charset=UTF-8" />
		<title>JSON</title>
	
		<script src="scripts/jquery/jquery-1.3.2.min.js" type="text/javascript"></script>
		<script src="scripts/jquery/json.js" type="text/javascript"></script>
		<script>
		
			$(document).ready(function (){
			var query="test";	
			 $.getJSON("jquery",null,function call(data){   wirteHtml(data);})	
				
			});
			
			function wirteHtml(data){   
				
				$.each(data.country,function(idx,item){
				
					if(idx==0){ 
						return true;//同countinue，返回false同break 
					} 
					alert(item.englishName);
				});
			
				alert(data.country.length);
				alert(data.country[0].englishName);
			}	
		</script>
	</head>
	<body>
	</body>

</html>
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1 楼 myali88 2009-12-10  
为什么我用$.getJSON请求返回的始终是一个JSON格式的string，并不能直接当JS对象使用？？？？
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